Adding front lights

[Texasgs]

hook them together, in series.
you will have to observe polarity as they are diodes after all.

That is it. When wire 2 of them up in series and apply 12 volts to them, each light only gets 6 volts. To hook it up in series connect one positive lead to the negative lead of the other light. Now tape up the wire. You will have a positive and a negative wire that are mot connected to anything. Now think of the pair as a single 12 volt light, and hook it up as you would any 12 volt light.

Dont worry about the battery rating it is completely irrelevant. If you want to figure out how much power the lights will consume it just takes a little math. You will need an ohm meter. After you have the two attached to each other in series, and before you apply power to them, measure the resistance in ohms, with the ohm meter. Divide the ohms of resistance into the volts. Dont use 12 for the volts, because the system will be at about 14 volts when the engine is on. So say the lights have .25 ohms of resistance. 14 devided by 2.5 = 5.6, so it would need 5.6 amps to operate. The amperage should be much lower, that is just an example of how to work the formula.

[Jagir]

That is it. When wire 2 of them up in series and apply 12 volts to them, each light only gets 6 volts. To hook it up in series connect one positive lead to the negative lead of the other light. Now tape up the wire. You will have a positive and a negative wire that are mot connected to anything. Now think of the pair as a single 12 volt light, and hook it up as you would any 12 volt light.

Dont worry about the battery rating it is completely irrelevant. If you want to figure out how much power the lights will consume it just takes a little math. You will need an ohm meter. After you have the two attached to each other in series, and before you apply power to them, measure the resistance in ohms, with the ohm meter. Divide the ohms of resistance into the volts. Dont use 12 for the volts, because the system will be at about 14 volts when the engine is on. So say the lights have .25 ohms of resistance. 14 devided by 2.5 = 5.6, so it would need 5.6 amps to operate. The amperage should be much lower, that is just an example of how to work the formula.

Thanks, this is what i was looking for. It may take some time as I am picking away at a stator replacement at the same time, but will post pictures when i get to it.

thanks again

[Kyoritsu]

you-know-whatley *@%^$*@%^$*@%^$s, Nice.